(x^2+y)(2x-y^5)=

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Solution for (x^2+y)(2x-y^5)= equation: 


Simplifying
(x2 + y)(2x + -1y5) = 0

Multiply (x2 + y) * (2x + -1y5)
(x2(2x + -1y5) + y(2x + -1y5)) = 0
((2x * x2 + -1y5 * x2) + y(2x + -1y5)) = 0

Reorder the terms:
((-1x2y5 + 2x3) + y(2x + -1y5)) = 0
((-1x2y5 + 2x3) + y(2x + -1y5)) = 0
(-1x2y5 + 2x3 + (2x * y + -1y5 * y)) = 0
(-1x2y5 + 2x3 + (2xy + -1y6)) = 0

Reorder the terms:
(2xy + -1x2y5 + 2x3 + -1y6) = 0
(2xy + -1x2y5 + 2x3 + -1y6) = 0

Solving
2xy + -1x2y5 + 2x3 + -1y6 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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